(x^2-5)(x^2-7x+12)=0

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Solution for (x^2-5)(x^2-7x+12)=0 equation:


Simplifying
(x2 + -5)(x2 + -7x + 12) = 0

Reorder the terms:
(-5 + x2)(x2 + -7x + 12) = 0

Reorder the terms:
(-5 + x2)(12 + -7x + x2) = 0

Multiply (-5 + x2) * (12 + -7x + x2)
(-5(12 + -7x + x2) + x2(12 + -7x + x2)) = 0
((12 * -5 + -7x * -5 + x2 * -5) + x2(12 + -7x + x2)) = 0
((-60 + 35x + -5x2) + x2(12 + -7x + x2)) = 0
(-60 + 35x + -5x2 + (12 * x2 + -7x * x2 + x2 * x2)) = 0
(-60 + 35x + -5x2 + (12x2 + -7x3 + x4)) = 0

Combine like terms: -5x2 + 12x2 = 7x2
(-60 + 35x + 7x2 + -7x3 + x4) = 0

Solving
-60 + 35x + 7x2 + -7x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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